Question

Match List-I with List-II.

Choose the correct answer from the options given below :

• A. (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
• B. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
• C. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
• D. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Hint:

Remember the definitions of the four basic thermodynamic processes: - Isothermal: constant temperature (\( \Delta T = 0 \), implies \( \Delta U = 0 \) for ideal gas).
- Adiabatic: no heat exchange (\( \Delta Q = 0 \)).
- Isobaric: constant pressure (\( \Delta P = 0 \)).
- Isochoric: constant volume (\( \Delta V = 0 \), implies \( \Delta W = 0 \)).

Answer 1

The Correct Option is C

Step 1: Analyze thermodynamic processes in List-I.
(A) Isothermal process: Constant temperature (\( \Delta T = 0 \)). For ideal gas, internal energy \( U \) is proportional to temperature. Thus, \( \Delta U = 0 \). (A) corresponds to (IV).
(B) Adiabatic process: No heat exchange with surroundings (\( \Delta Q = 0 \)). (B) corresponds to (II).
(C) Isobaric process: Constant pressure (\( \Delta P = 0 \)). Work done (\( \Delta W eq 0 \)), heat exchange (\( \Delta Q eq 0 \)), and change in internal energy (\( \Delta U eq 0 \)) occur. (C) corresponds to (III).
(D) Isochoric process: Constant volume (\( \Delta V = 0 \)). Work done \( \Delta W = P \Delta V = 0 \). (D) corresponds to (I).
Step 2: Match thermodynamic processes with characteristics.
(A) Isothermal - \( \Delta U = 0 \) - (IV)(B) Adiabatic - \( \Delta Q = 0 \) - (II)(C) Isobaric - \( \Delta U eq 0 \) - (III)(D) Isochoric - \( \Delta W = 0 \) - (I)
Step 3: Select the correct option.
The correct matching is (A)-(IV), (B)-(II), (C)-(III), (D)-(I), corresponding to option (3).