Question

Match List-I with List-II 

Choose the correct answer from the options given below: 
 

• (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
• (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
• (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
• (A) - (III), (B) - (IV), (C) - (II), (D) - (I)

Hint:

Associate keywords for chromatography types: Affinity \(\rightarrow\) Specific Binding; Ion-Exchange \(\rightarrow\) Charge; Size-Exclusion/Molecular Sieve \(\rightarrow\) Size; Partition/Adsorption \(\rightarrow\) Phase.

Answer 1

The Correct Option is D

Step 1: Chromatography Overview:
Chromatography is a lab technique used to separate mixtures. Separation relies on how mixture components distribute between a stationary and a mobile phase. Different chromatography types leverage distinct molecular properties for separation.
Step 2: Detailed Chromatography Types:
(A) Affinity Chromatography: This separates molecules based on specific biological interactions, like enzyme-substrate or antibody-antigen binding. The stationary phase has a ligand that binds the target molecule. Separation is based on specific Chemical Structure or binding affinity. Therefore, (A) matches (III).
(B) Ion-Exchange Chromatography: This method separates molecules based on their Charge. The stationary phase is a charged resin. Molecules with the opposite charge bind, while similarly charged or neutral molecules pass through. So, (B) matches (IV).
(C) Molecular Sieve Chromatography (Size-Exclusion/Gel Filtration): This separates molecules by Shape and Size. The stationary phase uses porous beads. Small molecules enter pores, increasing their path length. Large molecules cannot enter the pores and elute first. Hence, (C) matches (II).
(D) Planar Chromatography (e.g., Paper Chromatography, Thin-Layer Chromatography): Separation occurs as a mobile phase moves across a flat stationary phase. Separation depends on differential partitioning between the phases (stationary and mobile). Different component solubilities and adsorptions to the phases cause differing movement rates. Hence, (D) matches (I).
Step 3: Answer Summary:
The ideal matching is: (A)-(III), (B)-(IV), (C)-(II), (D)-(I). This doesn't precisely match any of the provided choices. Let's re-examine.
(A) Affinity \(\rightarrow\) (III) Chemical Structure (or Specific Binding)
(B) Ion-Exchange \(\rightarrow\) (IV) Charge
(C) Molecular Sieve \(\rightarrow\) (II) Shape and size
(D) Planar Chromatography \(\rightarrow\) (I) Phase (Partitioning between phases)
The mapping (A)-(III), (B)-(IV), (C)-(II), (D)-(I) is the most correct. Let's re-check the provided options. It seems an error is in the question's options. Let's determine the best fit. Let's suppose there's a typo in option 4, and it should be (A)-(III), (B)-(IV), (C)-(II), (D)-(I). If we must choose from the available choices, let's re-evaluate.
Option 4: (A)-(III), (B)-(IV), (C)-(I), (D)-(II) This correctly pairs A and B. It incorrectly matches (C) Molecular sieve with (I) Phase and (D) Planar with (II) Size. This is incorrect.
Let's check other options. None seem better. The question likely intended the mapping (A)-(III), (B)-(IV), (C)-(II), (D)-(I). Assuming a typo in the provided options and answer key, we will proceed with the logically correct pairing.
(A) Affinity \(\rightarrow\) (III) Chemical Structure
(B) Ion-Exchange \(\rightarrow\) (IV) Charge
(C) Molecular Sieve \(\rightarrow\) (II) Shape and size
(D) Planar \(\rightarrow\) (I) Phase
Considering the provided options, none are correct. However, if forced to select the "best" option, one would look for the option with the most correct pairs.
Option 1: A-I(X), B-II(X), C-III(X), D-IV(X)
Option 2: A-I(X), B-III(X), C-II(\checkmark), D-IV(X)
Option 3: A-I(X), B-II(X), C-IV(X), D-III(X)
Option 4: A-III(\checkmark), B-IV(\checkmark), C-I(X), D-II(X)
Option 4 has two correct matches, more than any other option. This strongly suggests that option 4 is the intended answer, despite errors.