Question:medium

Match List-I with List-II.}

Updated On: Jun 6, 2026
  • A-I, B-II, C-III, D-IV
  • A-II, B-III, C-IV, D-I
  • A-III, B-IV, C-I, D-II
  • A-IV, B-I, C-II, D-III
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Crystal Field Splitting Energy (\(\Delta_0\)) depends on the strength of the ligand according to the Spectrochemical Series.
Stronger ligands cause greater splitting of d-orbitals, resulting in a higher \(\Delta_0\) value.
Step 2: Key Formula or Approach:
The relative strength of common ligands is:
\(CN^->en>H_2O>F^-\).
Step 3: Detailed Explanation:
All complexes contain \(Cr^{3+}\) (\(d^3\)), so the only variable is the ligand.
- \(CN^-\) is a strong field ligand (highest in this list). It will have the maximum \(\Delta_0\).
Match: A \(\rightarrow\) IV (26,600).
- \(F^-\) is a weak field ligand (lowest in this list). It will have the minimum \(\Delta_0\).
Match: B \(\rightarrow\) I (15,060).
- \(en\) (ethylenediamine) is a stronger ligand than \(H_2O\).
Match: D \(\rightarrow\) III (22,300).
- \(H_2O\) is a medium strength ligand.
Match: C \(\rightarrow\) II (17,400).

The final match is: A-IV, B-I, C-II, D-III.
Step 4: Final Answer:
The correct match is A-IV, B-I, C-II, D-III.
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