Question

Match List I (species) with List II (hybridisation) and select the correct code given below \[ \begin{array}{c c c} List I & & List II A.\; XeF_4 & & (i)\; dsp^2 B.\; H_2O & & (ii)\; sp^3 C.\; PCl_5 & & (iii)\; sp^3d^2 D.\; [Pt(NH_3)_4]^{2+} & & (iv)\; sp^3d \end{array} \] Codes: {c c c c c} & A & B & C & D

• A. & (iii) & (ii) & (iv) & (i)
• B. & (i) & (iv) & (ii) & (iii)
• C. & (iii) & (iv) & (ii) & (i)
• D. & (i) & (ii) & (iv) & (iii)

Hint:

Square planar \(\Rightarrow\) \(dsp^2\), trigonal bipyramidal \(\Rightarrow\) \(sp^3d\), octahedral \(\Rightarrow\) \(sp^3d^2\).

Answer 1

The Correct Option is A

To correctly match the species in List I with their corresponding hybridisation in List II, we need to determine the hybridisation types for each species.

1. XeF₄: Xenon tetrafluoride involves one xenon atom and four fluoride atoms. The hybridisation of xenon here corresponds to \(sp^3d^2\). This is because xenon promotes one of its paired electrons from the p orbital to an empty d orbital, resulting in six hybridised orbitals forming a square planar configuration. Therefore, xenon tetrafluoride, \(\text{XeF}_{4}\), matches with (iii) \(sp^3d^2\).
2. H₂O: Water has a simple molecular composition with an oxygen atom using sp3 hybridisation to form two sigma bonds with hydrogen atoms and two lone pairs. Therefore, the hybridisation for water, \(H_2O\), is (ii) \(sp^3\).
3. PCl₅: Phosphorus pentachloride has a trigonal bipyramidal geometry. This requires five hybrid orbitals for bonding, resulting in \(sp^3d\) hybridisation. Thus, phosphorus pentachloride, \(PCl_5\), matches with (iv) \(sp^3d\).
4. [Pt(NH₃)₄]²⁺: The coordination number for this complex is 4, and it forms a square planar complex. Square planar complexes generally have a hybridisation of \(dsp^2\). Hence, the coordination complex, \([Pt(NH_3)_4]^{2+}\), matches with (i) \(dsp^2\).

Based on the above analysis, the correct matching of List I and List II is:

Species	Hybridisation
XeF4	(iii) \(sp^3d^2\)
H2O	(ii) \(sp^3\)
PCl5	(iv) \(sp^3d\)
[Pt(NH3)4]2+	(i) \(dsp^2\)

Thus, the correct match for List I and List II is the option:

& (iii) & (ii) & (iv) & (i)