List of top Chemistry Questions on Inorganic chemistry asked in MET

Electronegativity of the following elements increases in the order:
Which of the following species have same bond order? I. \( \mathrm{H_2} \)
II. \( \mathrm{B_2} \)
III. \( \mathrm{O_2^{2-}} \)
IV. \( \mathrm{Be_2} \)
V. \( \mathrm{N_2} \)
Correct option is:
Select the correct statement.
According to VSEPR theory, the molecular shapes of \(XeF_4\), \(XeO_4\), \(XeO_2F_2\) and \(XeOF_4\) respectively are
The reagent \(NH_4Cl\) and aqueous \(NH_3\) will precipitate:
Red hot iron absorbs \(SO_2\) giving the product.
Pure cold conc \(HNO_3\) makes iron passive, as the surface is covered with protective layer of
Which of the following statement is false?
\(K_2[HgI_4]\) detects the following ion:
Match List I with List II and choose the correct answer from the codes given below \[ \begin{array}{c c c} List I & & List II A.\; NaNO_3 & & (i)\; Baking\; soda B.\; Na(NH_4)HPO_4 & & (ii)\; Chile\; saltpetre C.\; NaHCO_3 & & (iii)\; Microcosmic\; salt D.\; Na_2CO_3 \cdot 10H_2O & & (iv)\; Washing\; soda \end{array} \] Codes: {c c c c c} & A & B & C & D
When \(MnO_2\) is heated with \(PbO_2\) and conc. \(HNO_3\), pink colour is obtained due to formation of:
Match List I (species) with List II (hybridisation) and select the correct code given below \[ \begin{array}{c c c} List I & & List II A.\; XeF_4 & & (i)\; dsp^2 B.\; H_2O & & (ii)\; sp^3 C.\; PCl_5 & & (iii)\; sp^3d^2 D.\; [Pt(NH_3)_4]^{2+} & & (iv)\; sp^3d \end{array} \] Codes: {c c c c c} & A & B & C & D
In qualitative analysis, \(NH_4Cl\) is added before \(NH_4OH\):
When CO\(_2\) is passed through solution of calcium hydroxide, which one of the following compound is precipitated?
Ferric alum has the composition (NH\(_4\))\(_2\)SO\(_4\)·Fe\(_2\)(SO\(_4\))\(_3\)·xH\(_2\)O. The value of x is
In the following reaction NaOH + S \(\rightarrow\) A + Na\(_2\)S + H\(_2\)O; A is
SiF\(_4\) gets hydrolysed giving
In the reaction, P\(_2\)O\(_5\) + 3CaO \(\rightarrow\) Ca\(_3\)(PO\(_4\))\(_2\), P\(_2\)O\(_5\) acts as
In the given reaction, the oxide of sodium is Na\(_2\)O + H\(_2\)O \(\rightarrow\) 2NaOH
Pure conc. HNO\(_3\) make iron passive, as the surface is covered with protective layer of
Ozone when reacts with potassium iodide solution liberates certain product, which turns starch paper blue. The liberated substance is
Red hot iron absorbs SO\(_2\) giving the product
The noble gas used for treatment of cancer is
Cane sugar on treating with conc. $\mathrm{H}_2\mathrm{SO}_4$ gives char. It is because $\mathrm{H}_2\mathrm{SO}_4$ is
The first compound of noble gas prepared by Bartlett was