Question:medium

Mass of methane required to produce 22 g of CO2​ after complete combustion is ______ g.
(Given Molar mass in g mol−1: C=12.0, H=1.0, O=16.0).

Updated On: Jan 13, 2026
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Correct Answer: 8

Solution and Explanation

The balanced chemical equation for the combustion of methane (CH4) is: CH4 + 2O2 → CO2 + 2H2O. To determine the mass of methane needed to yield 22 g of CO2, follow these steps:

Step 1: Calculate the molar mass of CO2

Molar mass of CO2 = Molar mass of C + 2 × Molar mass of O = 12.0 g/mol + 2 × 16.0 g/mol = 44.0 g/mol.

Step 2: Compute the moles of CO2 produced

Moles of CO2 = Mass of CO2 / Molar mass of CO2 = 22 g / 44.0 g/mol = 0.5 mol.

Step 3: Apply reaction stoichiometry to find moles of CH4

From the balanced equation, 1 mole of CH4 produces 1 mole of CO2. Thus, 0.5 mol of CO2 requires 0.5 mol of CH4.

Step 4: Determine the mass of CH4

Molar mass of CH4 = Molar mass of C + 4 × Molar mass of H = 12.0 g/mol + 4 × 1.0 g/mol = 16.0 g/mol.

Mass of CH4 = Moles of CH4 × Molar mass of CH4 = 0.5 mol × 16.0 g/mol = 8 g.

The required mass of methane is 8 g.

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