Major product 'P' formed in the following reaction is:
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The Hell-Volhard-Zelinsky (HVZ) reaction specifically brominates the α-carbon of car boxylic acids and can lead to lactone formation through intramolecular cyclization.
This is a typical example of a reaction involving bromination of a carboxylic acid derivative. The reaction given involves:
In the presence of \mathrm{Br}_2 and sodium bicarbonate (\mathrm{NaHCO}_3), the Hell-Volhard-Zelinsky (HVZ) reaction occurs. This reaction is specific for alpha-bromination of carboxylic acids. Here is a step-by-step mechanism:
The acid is first converted to its acid bromide by reaction with bromine.
Then, enolization occurs at the alpha position, where the hydrogen is abstracted.
The enol form reacts with bromine to form an alpha-bromo acid bromide.
Subsequent reaction with \mathrm{NaHCO}_3 helps to form the alpha-bromo acid as the major product.
In this reaction, the alpha position next to the carboxylic group is brominated.
Hence, the major product 'P' will be:
This confirms the product formed from the HVZ reaction mechanism, where the alpha position is selectively brominated. Thus, option with the image ID 65e715e89223295b81af8943 is the correct answer.
