Question:medium

Magnetic field at the centre of a circular coil of radius \( r \), through which a current \( I \) flows is:

Show Hint

The magnetic field at the centre of a circular coil is directly proportional to the current and inversely proportional to the radius of the coil. The formula is \( B = \frac{\mu_0 I}{2 r} \).
Updated On: Nov 26, 2025
  • directly proportional to \( r \)
  • inversely proportional to \( I \)
  • directly proportional to \( I \)
  • directly proportional to \( I^2 \)
Hide Solution

The Correct Option is C

Solution and Explanation

Step 1: Formula for Magnetic Field at the Centre of a Circular Coil
The magnetic field strength at the centre of a circular coil, when it carries a current \( I \), is calculated using the formula: \[ B = \frac{\mu_0 I}{2 r} \] In this equation:
\( \mu_0 \) denotes the permeability of free space,
\( I \) represents the current flowing through the coil,
\( r \) signifies the radius of the coil.
Step 2: Analyzing the Dependence of Magnetic Field

Analysis of the formula reveals that the magnetic field at the centre is directly proportional to the current \( I \) and inversely proportional to the radius \( r \).
Consequently, the magnetic field's proportionality is with \( I \) alone; it is not proportional to \( r \), nor is it proportional to \( I^2 \).Final Answer: The magnetic field at the centre of the circular coil exhibits direct proportionality to \( I \).
Was this answer helpful?
0