Question:medium

Locus of the mid-point of chord of circle \(x^2 + y^2 - 6x - 8y - 11 = 0\), subtending a right angle at the center is

Updated On: Apr 9, 2026
  • \(x^2 + y^2 - 6x - 8y + 7 = 0\)
  • \(x^2 + y^2 - 6x - 8y - 7 = 0\)
  • \(x^2 + y^2 + 6x + 8y - 7 = 0\)
  • \(x^2 + y^2 - 6x + 8y + 7 = 0\)
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The Correct Option is B

Solution and Explanation

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