Question:medium
\( \lim_{x \to \infty} \frac{3x^3 + 2x^2 - 7x + 9}{4x^3 + 9x - 2} \) is equal to
\( \lim_{x \to \infty} \frac{3x^3 + 2x^2 - 7x + 9}{4x^3 + 9x - 2} \) is equal to
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Only highest power terms matter for limits at infinity.
Updated On: May 1, 2026
- \( \frac{2}{9} \)
- \( \frac{1}{2} \)
- \( -\frac{9}{2} \)
- \( \frac{3}{4} \)
- \( \frac{9}{2} \)
Show Solution
The Correct Option is D
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