Question:medium
Let \(y = y(x)\) be the solution of the differential equation \(\frac{dy}{dx} = (1 + x + x^2)(1 - y + y^2)\), \(y(0) = \frac{1}{2}\). Then \((2y(1) - 1)\) is equal to:
Let \(y = y(x)\) be the solution of the differential equation \(\frac{dy}{dx} = (1 + x + x^2)(1 - y + y^2)\), \(y(0) = \frac{1}{2}\). Then \((2y(1) - 1)\) is equal to:
Updated On: Apr 10, 2026
- \(\sqrt{3} \tan \left( \frac{11\sqrt{3}}{6} \right)\)
- \(\frac{\sqrt{3}}{2} \tan \left( \frac{11\sqrt{3}}{12} \right)\)
- \(\sqrt{3} \tan \left( \frac{11\sqrt{3}}{12} \right)\)
- \(\frac{\sqrt{3}}{2} \tan \left( \frac{11\sqrt{3}}{6} \right)\)
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The Correct Option is C
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