Question:medium
Let \(y=y(x)\) be the solution curve of the differential equation}
\[
(1+\sin x)\frac{dy}{dx}+(y+1)\cos x=0,\qquad y(0)=0.
\]
If the curve passes through the point \( \left(\alpha,-\frac12\right) \), then a value of \( \alpha \) is:
Let \(y=y(x)\) be the solution curve of the differential equation}
\[
(1+\sin x)\frac{dy}{dx}+(y+1)\cos x=0,\qquad y(0)=0.
\]
If the curve passes through the point \( \left(\alpha,-\frac12\right) \), then a value of \( \alpha \) is:
Updated On: Apr 10, 2026
- \( \frac{\pi}{6} \)
- \( \frac{\pi}{4} \)
- \( \frac{\pi}{3} \)
- \( \frac{\pi}{2} \)
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The Correct Option is C
Solution and Explanation
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