Question:medium
Let \( x = x(y) \) be the solution of the differential equation}
\[
2y^2 \frac{dx}{dy} - 2xy + x^2 = 0, \quad y>1, \quad x(e) = e.
\]
Then \( x(e^2) \) is equal to:
Let \( x = x(y) \) be the solution of the differential equation}
\[
2y^2 \frac{dx}{dy} - 2xy + x^2 = 0, \quad y>1, \quad x(e) = e.
\]
Then \( x(e^2) \) is equal to:
Updated On: Apr 10, 2026
- \( \frac{3}{2} e^2 \)
- \( \frac{2}{3} e^2 \)
- \( e^2 \)
- \( 2e^2 \)
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The Correct Option is C
Solution and Explanation
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