Question

Let \(X\) have a binomial distribution \(B(6,p)\). If the sum of the mean and the variance of \(X\) is \(\dfrac{21}{8}\), then \[ \frac{P(2\le X<4)}{P(4<X<6)} \] is equal to:

• A. \(65\)
• B. \(195\)
• C. \(\dfrac{195}{2}\)
• D. \(\dfrac{225}{2}\)

Hint:

For binomial problems, first determine \(p\) using mean and variance, then compute only the required terms instead of full probability tables.

Answer 1

The Correct Option is C