Question:medium

Let the line $ y - x = 1 $ intersect the ellipse $ \frac{x^2}{2} + \frac{y^2}{1} = 1 $ at the points A and B. Then the angle made by the line segment AB at the center of the ellipse is:

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To homogenize, ensure the line equation is in the form of "Expression = 1". Substitute this "1" into the constant or second-degree terms of the curve to make all terms degree 2.

Updated On: Mar 30, 2026

$ \frac{\pi}{2} - \tan^{-1}\left(\frac{1}{4}\right) $
$ \frac{\pi}{2} + 2 \tan^{-1}\left(\frac{1}{4}\right) $
$ \frac{\pi}{2} + \tan^{-1}\left(\frac{1}{4}\right) $
$ \pi - \tan^{-1}\left(\frac{1}{4}\right) $

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The Correct Option is C

Solution and Explanation

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Questions Asked in JEE Main exam

Six point charges are kept $60^\circ$ apart from each other on the circumference of a circle of radius $ R $ as shown in figure. The net electric field at the center of the circle is ___________. ($ \varepsilon_0 $ is permittivity of free space)