To solve this problem, we first need to understand the composition of the power set of set \( S \), denoted as \( P(S) \). Given that set \( S \) has 5 elements, it follows that its power set \( P(S) \) has \( 2^5 = 32 \) elements. This is because the power set of a set with \( n \) elements contains \( 2^n \) subsets.
We are asked to calculate the probability that the intersection of two randomly selected subsets \( A \) and \( B \) from the power set is an empty set, i.e., \( A \cap B = \varnothing \).
Step 1: Total Number of Ordered Pairs
- The total number of ordered pairs \( (A, B) \) is \( |P(S) \times P(S)| = 32 \times 32 = 1024 \).
Step 2: Determining Pairs with Empty Intersection
- To ensure \( A \cap B = \varnothing \), no element of \( S \) should be in both \( A \) and \( B \) at the same time.
- Each element in \( S \) can either be in \( A \) or \( B \) or in neither. That gives us 3 choices per element of \( S \).
- Therefore, for 5 elements, the total number of ways to choose such pairs \( (A, B) \) where \( A \cap B = \varnothing \) is \( 3^5 \).
- Thus, there are \( 3^5 = 243 \) pairs where \( A \cap B = \varnothing \).
Step 3: Calculating the Probability
- The probability that \( A \cap B = \varnothing \) is given by the ratio of favorable outcomes to total outcomes:
\(\frac{243}{1024}\).
Step 4: Expressing the Probability
- Expressing \( \frac{243}{1024} \) in terms of powers of 3 and 2, we get \( \frac{3^5}{2^{10}} \).
- Thus, this can be written as \(\frac{3^m}{2^n}\) where \( m = 5 \) and \( n = 10 \).
Step 5: Calculating \( m + n \)
- The value of \( m+n \) is \( 5 + 10 = 15 \).
- It appears there is a typographical or conceptual discrepancy in the output and given correct answer.
Conclusion: Thus, according to the method and calculations, \( m+n \) should be 15. However, it seems logic or problem discrepancy might adjust the official provided answer being 96. Verification is essential against alternative question or calculative options.