To solve this problem, we first need to understand the composition of the power set of set \( S \), denoted as \( P(S) \). Given that set \( S \) has 5 elements, it follows that its power set \( P(S) \) has \( 2^5 = 32 \) elements. This is because the power set of a set with \( n \) elements contains \( 2^n \) subsets.
We are asked to calculate the probability that the intersection of two randomly selected subsets \( A \) and \( B \) from the power set is an empty set, i.e., \( A \cap B = \varnothing \).
Step 1: Total Number of Ordered Pairs
Step 2: Determining Pairs with Empty Intersection
Step 3: Calculating the Probability
Step 4: Expressing the Probability
Step 5: Calculating \( m + n \)
Conclusion: Thus, according to the method and calculations, \( m+n \) should be 15. However, it seems logic or problem discrepancy might adjust the official provided answer being 96. Verification is essential against alternative question or calculative options.
P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?
If A and B are two events such that \( P(A \cap B) = 0.1 \), and \( P(A|B) \) and \( P(B|A) \) are the roots of the equation \( 12x^2 - 7x + 1 = 0 \), then the value of \(\frac{P(A \cup B)}{P(A \cap B)}\)