Question:medium

Let \( PQR \) be a triangle such that \[ \vec{PQ}=-2\hat i-\hat j+2\hat k,\quad \vec{PR}=a\hat i+b\hat j-4\hat k,\ a,b\in\mathbb{Z}. \] Let \( S \) be the point on \( QR \) which is equidistant from the lines \( PQ \) and \( PR \). If \[ |\vec{PR}|=9 \quad \text{and} \quad \vec{PS}=\hat i-7\hat j+2\hat k, \] then the value of \( 3a-4b \) is:

Show Hint

For equidistance from two lines through a point, always apply the angle-bisector condition using direction vectors.
Updated On: Feb 24, 2026
Show Solution

Correct Answer: 29

Solution and Explanation

Was this answer helpful?
3

Top Questions on Vector Algebra


Questions Asked in JEE Main exam