Question:medium

Let \(\omega\) is an imaginary cube root of unity, then the value of \(2(1+\omega)(1+\omega^2) + 3(2\omega+1)(2\omega^2+1) + \cdots + (n+1)(n\omega+1)(n\omega^2+1)\) is

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\(1 + \omega + \omega^2 = 0\), \(\omega^3 = 1\), \(\omega^2 = \bar{\omega}\).

Updated On: Apr 7, 2026

\(\left[\frac{n(n+1)}{2}\right]^2 + n\)
\(\left[\frac{n(n+1)}{2}\right]^2\)
\(\left[\frac{n(n+1)}{2}\right]^2 - n\)
None of these

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The Correct Option is A

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Questions Asked in MET exam

If \(f(x) = \begin{cases} x, & 0 \le x \le 1 \\ 2x - 1, & 1<x \end{cases}\), then

MET - 2019
Continuity

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