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let f x begin cases x 3 8...
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Let \[ f(x)= \begin{cases} x^3+8, & x<0,\\ x^2-4, & x\ge0, \end{cases} \qquad g(x)= \begin{cases} (x-8)^{1/3}, & x<0,\\ (x+4)^{1/2}, & x\ge0. \end{cases} \] Then the number of points where the function \(g\circ f\) is discontinuous is ______.
JEE Main - 2026
JEE Main
Updated On:
Apr 12, 2026
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2
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