Question:medium
Let $f: [1, \infty) \to \mathbb{R}$ be a differentiable function defined as $f(x) = \int_1^x f(t) dt + (1-x)(\log_e x - 1) + e$. Then the value of $f(f(1))$ is :
Let $f: [1, \infty) \to \mathbb{R}$ be a differentiable function defined as $f(x) = \int_1^x f(t) dt + (1-x)(\log_e x - 1) + e$. Then the value of $f(f(1))$ is :
Updated On: Apr 12, 2026
- $(1 + e^e)$
- $(1 + e)$
- $(1 + e + e^e)$
- $1 + 2e$
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The Correct Option is A
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