Question:medium

Let \(C_1\) and \(C_2\) be concentric circles such that the diameter of \(C_1\) is 2 cm longer than that of \(C_2\). If a chord of \(C_1\) has length 6 cm and is a tangent to \(C_2\), then the diameter, in cm, of \(C_1\) is
[This Question was asked as TITA]

Updated On: Jan 15, 2026
  • 10 cm
  • 12 cm
  • 15 cm
  • 18 cm
Show Solution

The Correct Option is A

Solution and Explanation

Given: \( d + 2 = D \Rightarrow r + 1 = R \)

In the provided diagram, the small circle's radius is denoted by \( r \). Consequently:

  • \( OT = r \) represents the radius of the smaller circle.
  • \( OB = r + 1 = R \) represents the radius of the larger circle.
  • The line segment AB is tangent to the smaller circle at point T, meaning it is perpendicular to the radius OT.
  • Thus, \( OT \perp AB \).
  • Furthermore, OT bisects AB, resulting in \( TB = \frac{6}{2} = 3 \, \text{cm} \).

Applying the Pythagorean theorem to the right-angled triangle \( \triangle OTB \):

\[ OT^2 + TB^2 = OB^2 \]

Substituting the known values:

\[ r^2 + 3^2 = (r + 1)^2 \]

Expanding the equation:

\[ r^2 + 9 = r^2 + 2r + 1 \]

Simplifying by canceling \( r^2 \) from both sides:

\[ 9 = 2r + 1 \Rightarrow 2r = 8 \Rightarrow r = 4 \]

With \( r = 4 \), the radius of the larger circle is \( R = r + 1 = 5 \).

The diameter of the larger circle is calculated as: \[ D = 2R = 2 \times 5 = \mathbf{10 \, \text{cm}} \]

Correct option: (A) 10 cm

Was this answer helpful?
0


Questions Asked in CAT exam