Question:medium

Let \(A\) and \(B\) be two events such that one of the two events must occur. Given that the chance of occurrence of \(A\) is \( \frac{2}{3} \) the chance of occurrence of \(B\), then odds in favour of \(B\) is

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Odds in favour of an event = Probability of event : Probability of its complement.
Updated On: Apr 28, 2026
  • \(3:5\)
  • \(2:5\)
  • \(3:2\)
  • \(2:3\)
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The Correct Option is C

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