To find the number of elements in the relation \( R \), we first need to understand the condition given:
We are given a relation \( R = \{ ((a_1, b_1), (a_2, b_2)) \in (A \times B, A \times B) : a_1 \text{ divides } b_2 \text{ and } a_2 \text{ divides } b_1 \} \).
We have sets \( A = \{2, 3, 4\} \) and \( B = \{8, 9, 12\} \). The Cartesian product \( A \times B \) would yield all possible pairs \((a_i, b_j)\) where \( a_i \in A \) and \( b_j \in B \).
First, let's calculate the Cartesian product \( A \times B \). This will give us all pairs \((a, b)\) such that \( a \in A \) and \( b \in B \).
| A | B | Pairs in \( A \times B \) |
|---|---|---|
| 2 | 8 | (2, 8) |
| 2 | 9 | (2, 9) |
| 2 | 12 | (2, 12) |
| 3 | 8 | (3, 8) |
| 3 | 9 | (3, 9) |
| 3 | 12 | (3, 12) |
| 4 | 8 | (4, 8) |
| 4 | 9 | (4, 9) |
| 4 | 12 | (4, 12) |
There are \( 3 \times 3 = 9 \) pairs in the Cartesian product \( A \times B \). Now, construct the set \((A \times B, A \times B)\), which means we have to pair every element of \( A \times B \) with every other element, leading to \((9 \times 9) = 81\) possible pairs.
Next, count the number of tuple pairs ((a1, b1), (a2, b2)) which satisfy the condition:
1. \( a_1 \) divides \( b_2 \)
2. \( a_2 \) divides \( b_1 \)
Let's evaluate the division:
For each \( b_1 \), calculate possible \( a_2 \):
Now consider all combinations where each \( b_2 \) matches possible \( a_1 \), and each \( b_1 \) matches possible \( a_2 \):
Thus, the number of elements in the relation \( R \) is 36, confirming option 36 as the correct answer.