Let $ A = \{-2, -1, 0, 1, 2, 3\} $. Let $ R $ be a relation on $ A $ defined by $ (x, y) \in R $ if and only if $ |x| \le |y| $. Let $ m $ be the number of reflexive elements in $ R $ and $ n $ be the minimum number of elements required to be added in $ R $ to make it reflexive and symmetric relations, respectively. Then $ l + m + n $ is equal to
Given set \(A = \{-2, -1, 0, 1, 2, 3\}\) and a relation R on A defined by \(y = \max\{x, 1\}\). We are required to determine \(l\), the cardinality of R; \(m\), the minimum number of elements to add to R to make it reflexive; and \(n\), the minimum number of elements to add to R to make it symmetric. The objective is to compute \(l + m + n\).
A relation R on set A is a subset of \(A \times A\).
A relation R on A is reflexive if \((a, a) \in R\) for all \(a \in A\).
A relation R on A is symmetric if for every \((a, b) \in R\), it implies \((b, a) \in R\).
Step 1: Determine R and its size, \(l\).
The relation is defined by \(y = \max\{x, 1\}\) for \(x, y \in A\). Evaluating for each \(x \in A\):
Thus, \(R = \{(-2, 1), (-1, 1), (0, 1), (1, 1), (2, 2), (3, 3)\}\).
The cardinality of R is \(l\).
\[l = 6\]Step 2: Determine \(m\), the count of elements to add for reflexivity.
For R to be reflexive on A, it must include all pairs \((a, a)\) for \(a \in A\).
The complete set of reflexive pairs is \(R_{\text{reflexive\_pairs}} = \{(-2, -2), (-1, -1), (0, 0), (1, 1), (2, 2), (3, 3)\}\).
R already contains \((1, 1), (2, 2), (3, 3)\). The missing pairs are \(\{(-2, -2), (-1, -1), (0, 0)\}\).
The minimum number of elements to add is:
\[m = 3\]Step 3: Determine \(n\), the count of elements to add for symmetry.
For R to be symmetric, if \((a, b) \in R\), then \((b, a)\) must also be in R.
The pairs to be added for symmetry are \(\{(1, -2), (1, -1), (1, 0)\}\).
The minimum number of elements to add is:
\[n = 3\]Step 4: Compute \(l + m + n\).
Using \(l=6\), \(m=3\), and \(n=3\):
\[l + m + n = 6 + 3 + 3 = 12\]The value of \(l + m + n\) is 12.