\( K_a \) for \( \text{CH}_3 \text{COOH} \) is \( 1.8 \times 10^{-5} \) and \( K_b \) for \( \text{NH}_4 \text{OH} \) is \( 1.8 \times 10^{-5} \). The pH of ammonium acetate solution will be:

Question

Arrange the following resultant mixtures in increasing order of their pH values}
A. \(10 \text{ mL } 0.2 \text{ M Ca(OH)}_2 + 25 \text{ mL } 0.1 \text{ M HCl}\)
B. \(10 \text{ mL } 0.01 \text{ M H}_2\text{SO}_4 + 10 \text{ mL } 0.01 \text{ M Ca(OH)}_2\)
C. \(10 \text{ mL } 0.1 \text{ M H}_2\text{SO}_4 + 10 \text{ mL } 0.1 \text{ M KOH}\)

Answer 1

The pH is calculated as:

\(\text{pH} = \frac{pK_a + pK_b}{2}\)

Given that \(pK_a = pK_b\),

\(\text{pH} = \frac{7 + 7}{2} = 7\)

\( K_a \) for \( \text{CH}_3 \text{COOH} \) is \( 1.8 \times 10^{-5} \) and \( K_b \) for \( \text{NH}_4 \text{OH} \) is \( 1.8 \times 10^{-5} \). The pH of ammonium acetate solution will be:

Correct Answer: 7

Solution and Explanation

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