Question:medium

\(K_2[HgI_4]\) detects the following ion:

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Nessler's reagent (\(K_2[HgI_4]\)) → test for NH\(_4^+\) (brown precipitate).
Updated On: May 21, 2026
  • Cl\(^{-}\)
  • NO\(_2^{-}\)
  • NO\(_3^{-}\)
  • NH\(_4^{+}\)
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The Correct Option is D

Solution and Explanation

The compound \(K_2[HgI_4]\) is known to detect the ammonium ion, \(NH_4^+\). Here's a step-by-step explanation of how it works:

Understanding the Compound: The compound \(K_2[HgI_4]\) is potassium tetraiodomercurate(II). It is used in various chemical tests due to its ability to form insoluble complexes with certain ions.

Chemical Reaction: When ammonium ions are present in a solution, they react with the potassium tetraiodomercurate(II) to form a distinctive white precipitate. The reaction can be summarized as:

\(NH_4^+ + K_2[HgI_4] \rightarrow (NH_4)_2[HgI_4]\)

The formation of the white precipitate of ammonium tetraiodomercurate(II) indicates the presence of ammonium ions.

Ruling Out Other Ions: The other ions given in the options (Cl\(^-\), NO\(_2^-\), and NO\(_3^-\)) do not form such a precipitate with \(K_2[HgI_4]\). This specificity makes it a reliable test for \(NH_4^+\) ions.

Conclusion: The correct answer is \(NH_4^+\) because it is the only ion among the options that forms a characteristic precipitate with \(K_2[HgI_4]\).

Understanding this reaction is crucial for identifying ammonium ions in qualitative analysis in chemistry.

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