Question

$\int \frac{1+\cos 4x}{\cot x - \tan x} dx =$

• A. $\frac{1}{4} \cos 4x + c$
• B. $\frac{1}{8} \cos 4x + c$
• C. $-\frac{1}{4} \cos 4x + c$
• D. $-\frac{1}{8} \cos 4x + c$

Hint:

$\cot x - \tan x = 2 \cot 2x$ is a very common identity in calculus.

Answer 1

The Correct Option is D