Question:medium

$\int_{a}^{b} (|x-a| + |x-b|) dx = , (0 < a < b)$

Show Hint

Between $a$ and $b$, the sum of distances $|x-a| + |x-b|$ is always constant and equal to the distance between the endpoints, $(b-a)$.
  • $(b-a)^2$
  • $(b-a)$
  • $(b+a)$
  • $(b+a)^2$
Show Solution

The Correct Option is A

Solution and Explanation

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