Question:medium

$\int_{-2}^{4} |2-x^2| dx =$

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When integrating an absolute value function $|f(x)|$, first find the roots of $f(x)=0$. These roots are the points where you need to split the interval of integration. Then, for each sub-interval, determine the sign of $f(x)$ to remove the absolute value bars correctly.

Updated On: Mar 30, 2026

$\frac{8\sqrt{2}-3}{3}$
$\frac{16\sqrt{2}}{3}+12$
$\frac{16\sqrt{2}-3}{3}$
$\frac{8\sqrt{2}+12}{3}$

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The Correct Option is B

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