Question:medium

In which of the following sets, reagents required to convert propene (X) to an amine (Y) with one carbon atom more than X, are correctly arranged? I. \(HBr/(C_6H_5CO)_2O_2;\ NH_3\) II. \(HBr;\ AgCN;\ H_2/Ni\) III. \(HBr/(C_6H_5CO)_2O_2;\ NaCN/C_2H_5OH;\ LiAlH_4,H_2O\) IV. \(HBr/(C_6H_5CO)_2O_2;\ AgNO_2;\ Sn,HCl\)

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Whenever a question asks for an amine with one extra carbon atom, think of the sequence: \[ R-X \rightarrow R-CN \rightarrow R-CH_2NH_2 \] using KCN/NaCN followed by reduction.
Updated On: Jun 17, 2026
  • I, II only
  • I, IV only
  • II, III only
  • III, IV only
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The Correct Option is C

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