To solve this question, we need to evaluate each option's validity based on the given property trend.
- Option (a): BF\(_3\)>NF\(_3\)>NH\(_3\) - Dipole moment:
- BF\(_3\) is a symmetrical molecule with zero dipole moment.
- NF\(_3\), on the other hand, has a lower dipole moment than NH\(_3\), because the nitrogen-fluorine bond is less polar than the nitrogen-hydrogen bond, and the lone pair's effect is less dominant in NF\(_3\).
- The actual correct order should be NH\(_3\) > NF\(_3\) > BF\(_3\). Therefore, this statement does not agree with the variation in dipole moments, making it incorrect.
- Option (b): HgCl\(_2\)>NH\(_4\)\(^+\)>SF\(_4\) - Bond angle:
- HgCl\(_2\) is linear with a bond angle of 180°. NH\(_4\)\(^+\) is tetrahedral with a bond angle of approximately 109.5°, and SF\(_4\) is seesaw-shaped, with bond angles less than 109.5°.
- The order given in the option is correct.
- Option (c): NH\(_3\)<H\(_2\)O<HF - Strength of intermolecular hydrogen bonding:
- HF forms the strongest hydrogen bonds among the given molecules, followed by H\(_2\)O, then NH\(_3\).
- The order given is correct.
- Option (d): H - I>H - Br>H – Cl - Bond length:
- The bond length decreases with increasing bond strength, and the bond strength increases as we move up the halogen group.
- Therefore, H–I > H–Br > H–Cl is the correct bond length order.
Based on the above analysis, the correct answer is that only option (a) fails to follow the trend indicated. Hence, the correct answer is: a only.