Question

$$ \int_{0}^{\pi/4} (\tan^8 x + \tan^6 x) \, dx = ? $$

• A. $\frac{1}{3}$
• B. $\frac{1}{2}$
• C. $\frac{1}{5}$
• D. $\frac{1}{7}$

Hint:

Reduction formula hint: $\int (\tan^n x + \tan^{n-2} x) \, dx = \frac{\tan^{n-1} x}{n-1}$. For $n=8$, the answer is simply $1/(8-1) = 1/7$.

Answer 1

The Correct Option is D