Question:medium

In which of the following, elements are not in correct order with respect to the property mentioned in brackets?

Show Hint

When evaluating "not in correct order" questions, always check for common anomalies like full-filled/half-filled orbitals in Ionization Enthalpy and specific group vs. period positioning for Electronegativity.
Updated On: Jun 7, 2026
  • \( S < P < N < O \) (Electronegativity)
  • \( Br < Ge < Ga < Ca \) (Atomic radius)
  • \( Al < Mg < S < P \) (First ionization enthalpy)
  • \( Mg < Ca < K < Cs \) (Metallic nature)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Note the four trends we need.
Across a period (left to right): electronegativity rises, atomic radius shrinks, ionization energy rises, metallic nature falls. Down a group the opposite happens.
Step 2: Check the electronegativity option.
The true order is $O>N>S>P$, so written small to big it is $P<S<N<O$. The option gives $S<P<N<O$, which swaps S and P. So this one is wrong, but let us check all to be sure.
Step 3: Check the atomic radius option.
For period 4, radius falls left to right, so $Ca>Ga>Ge>Br$. Written small to big that is $Br<Ge<Ga<Ca$. This matches, so it is correct.
Step 4: Check the ionization energy option.
Half filled $3p^3$ in P and filled $3s^2$ in Mg are extra stable, giving $P>S$ and $Mg>Al$. So $Al<Mg<S<P$ is correct.
Step 5: Check the metallic nature option.
Metallic nature grows down a group and group 1 beats group 2. So $Mg<Ca<K<Cs$ is correct.
Step 6: Pick the odd one.
Only the electronegativity option breaks the rule because P and S are placed the wrong way round. \[ \boxed{S<P<N<O\ \text{is the wrong order}} \]
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