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The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of

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The atomicity of sulfur \( (S_8) \) results in stronger intermolecular forces compared to oxygen \( (O_2) \), leading to a higher melting and boiling point for sulfur.
Updated On: Jan 14, 2026
  • Atomic size
  • Atomicity
  • Electronegativity
  • Electron gain enthalpy
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The Correct Option is B

Solution and Explanation

The substantial disparity in the melting and boiling points of oxygen (O2) and sulfur (S8) is principally attributed to their atomicity.

  1. Atomicity: This term denotes the number of atoms comprising a molecule. Oxygen is found as a diatomic molecule (O2), comprising two atoms. Conversely, sulfur commonly exists as an octatomic molecule (S8), composed of eight atoms.
  2. Intermolecular Forces: The S8 molecular configuration of sulfur renders it larger and more intricate. This complexity leads to more robust van der Waals attractive forces between its molecules when juxtaposed with O2. Overcoming these intensified forces necessitates greater energy input, resulting in elevated melting and boiling points for sulfur relative to oxygen.
  3. Evaluation of Factors:
    • Atomic Size: While atomic size does influence melting and boiling points, the differential atomicity is the more dominant factor in this specific comparison.
    • Electronegativity: Electronegativity does not exert a direct impact on the melting or boiling points in this scenario.
    • Electron Gain Enthalpy: This property pertains to the energy shift upon electron addition to an atom and is unrelated to the determination of melting and boiling points.
  4. Synopsis: The primary determinant for the significant difference in melting and boiling points between oxygen and sulfur is their respective atomicity. The distinct molecular structures (O2 versus S8) are responsible for variations in the strength of intermolecular forces, thereby influencing their phase transition temperatures.
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