In which of the following compounds does the oxidation number of oxygen equal +2?

Question

Consider the reactions: 1. \(NaCl+K_{2}Cr_{2}O_{7}+H_{2}SO_{4} \rightarrow A + ...\) 2. \(A + NaOH \rightarrow B + ...\) 3. \(B + H_{2}SO_{4}+H_{2}O_{2} \rightarrow C + ...\) In the product 'C', X is the number of \(O_{2}^{2-}\) units, Y is the total number of oxygen atoms, and Z is the oxidation state of Cr. The value of \(X+Y+Z\) is__.

Answer 1

In sodium peroxide (\( Na_2O_2 \)), oxygen's oxidation number is -1 within the peroxide ion (\( O_2^{2-} \)). Conversely, in \( F_2O \), oxygen exhibits an oxidation state of +2 due to fluorine's higher electronegativity. Ozone (\( O_3 \)) features an oxidation state of 0 for oxygen. Therefore, \( F_2O \) is the compound where oxygen's oxidation number is +2.

In which of the following compounds does the oxidation number of oxygen equal +2?

Show Hint

The Correct Option is B

Solution and Explanation

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