Question

In terms of Planck's constant (h), permittivity of free space \((\epsilon_{0})\), mass of the electron (m) and charge of the electron (e), the de Broglie wavelength associated with the electron in the second orbit of hydrogen atom is

• A. \(\frac{h^{2}\epsilon_{0}}{2me^{2}}\)
• B. \(\frac{h^{2}\epsilon_{0}}{4me^{2}}\)
• C. \(\frac{2h^{2}\epsilon_{0}}{me^{2}}\)
• D. \(\frac{4h^{2}\epsilon_{0}}{me^{2}}\) \bigskip

Hint:

For the \(n^{th}\) orbit, \[ \lambda_n=\frac{2\pi r_n}{n} \] Using Bohr radius expressions directly saves a lot of calculation time in competitive examinations.

Answer 1

The Correct Option is D