In photoelectric experiment energy of 2.48 eV irradiates a photo sensitive material. The stopping potential was measured to be 0.5 V. Work function of the photo sensitive material is :

Question

Light is incident on a metallic plate having work function $110 \times 10^{-20}\,\text{J}$. If the produced photoelectrons have zero kinetic energy, then the angular frequency of the incident light is _________ rad/s. ($h = 6.63 \times 10^{-34}\,\text{J·s}$)}

Answer 1

Photoelectric effect energy relation:

\[ eV_s = hu - \phi \]

Here, $eV_s$ denotes the stopping potential energy, $hu$ represents the incident photon energy, and $\phi$ is the work function.

Given: Incident photon energy $hu = 2.48 \, \text{eV}$, Stopping potential $V_s = 0.5 \, \text{V}.$

Substituting the given values:

\[ 0.5 = 2.48 - \phi \]

Solving for the work function:

\[ \phi = 2.48 - 0.5 = 1.98 \, \text{eV}. \]

The work function of the material is $\phi = 1.98 \, \text{eV}.$

In photoelectric experiment energy of 2.48 eV irradiates a photo sensitive material. The stopping potential was measured to be 0.5 V. Work function of the photo sensitive material is :

The Correct Option is D

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