Question

In $KO_2$, the nature of oxygen species and the oxidation state of oxygen atom are, respectively :

• A. Oxide and -2
• B. Superoxide and -1/2
• C. Peroxide and -1/2
• D. Superoxide and -1

Answer 1

The Correct Option is B

To answer this question, we need to determine the nature of the oxygen species in KO_2 and the oxidation state of the oxygen atom.

Step 1: Identify the Compound

The chemical formula KO_2 represents potassium superoxide.

Step 2: Nature of Oxygen Species

In KO_2, the oxygen species present is the superoxide anion O_2^-\text{.} In superoxides, the oxygen-oxygen bond involves a single bond with one extra electron spread across the two oxygens, sharing a -1 charge.

Step 3: Determine the Oxidation State of Oxygen

Superoxide can be described as O_2^-\text{.} The charge is distributed over the two oxygen atoms, so each oxygen in the superoxide ion has an oxidation state of -\frac{1}{2}\text{.}

Conclusion

Therefore, in KO_2, the nature of the oxygen species is "Superoxide," and the oxidation state of each oxygen atom is -\frac{1}{2}\text{.}

Correct Choice: Superoxide and -1/2