In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is ___________%. [Given: Molar mass in g mol\(^{-1}\) of Ag = 108, Cl = 35.5]
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To calculate the percentage composition of an element, divide the mass of the element by the total mass of the compound and multiply by 100.
The moles of Cl present in AgCl are calculated as \( n_{\text{Cl}} = n_{\text{AgCl}} = \frac{143.5 \times 10^{-3}}{143.5} = 10^{-3} \). The percentage composition of Cl is determined by the formula \[ \% \text{Cl} = \frac{10^{-3} \times 35.5}{180 \times 10^{-3}} \times 100 = 19.72 \% \]. Therefore, the percentage composition of chlorine is approximately 20%.
