Question:medium

In an isosceles right angled triangle ABC, the equal sides AB and AC are 10 cm. Charges \(+5\mu C\), \(+20\mu C\) and \(+20\mu C\) are placed at A, B and C respectively. A charge \(+2\mu C\) is placed at the midpoint of BC. The net electrostatic force on it is:

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At the midpoint of the hypotenuse of a right triangle, distances from all three vertices are equal.
Updated On: Jun 18, 2026
  • \(24N\)
  • \(9N\)
  • \(36N\)
  • \(18N\)
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The Correct Option is D

Solution and Explanation

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