Question:medium
Two identical point charges are placed at the two vertices A and B of an equilateral triangle of side \( l \). The magnitude of the electric field at the third vertex P is \( E \). If a hollow conducting sphere of radius \( l/4 \) is placed at P, the magnitude of the electric field at point P now becomes:
Two identical point charges are placed at the two vertices A and B of an equilateral triangle of side \( l \). The magnitude of the electric field at the third vertex P is \( E \). If a hollow conducting sphere of radius \( l/4 \) is placed at P, the magnitude of the electric field at point P now becomes:
Show Hint
The electric field inside a conductor is always zero in electrostatic equilibrium.
Updated On: Feb 10, 2026
- \( >E \)
- \( E \)
- \( \frac{E}{2} \)
- zero
Show Solution
The Correct Option is D
Solution and Explanation
An equilateral triangle has two identical point charges at vertices A and B, creating an electric field \( E \) at point P. When a conducting sphere is introduced at point P, the electric field within the conductor becomes zero. This occurs due to the redistribution of free charges within the conductor, which neutralize the external electric field. Consequently, the electric field at point P is eliminated upon placement of the conducting sphere, aligning with option (D).
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