Question

In an experiment with photoelectric effect, the stopping potential:

• A. increases with increase in the wavelength of the incident light
• B. increases with increase in the intensity of the incident light
• C. is \( \frac{1}{e} \) times the maximum kinetic energy of the emitted photoelectrons
• D. decreases with increase in the intensity of the incident light

Hint:

The stopping potential \( V_s \) is a key factor in the photoelectric effect, representing the potential needed to stop the emitted electrons. It is directly related to the maximum kinetic energy of the emitted photoelectrons.

Answer 1

The Correct Option is C

The photoelectric effect describes the energy of emitted photoelectrons using the equation: \[ E = h u - W \] Here, \( h u \) represents the energy of the incident photons, and \( W \) is the work function. The stopping potential \( V_s \) is directly proportional to the kinetic energy of the emitted photoelectrons, as defined by: \[ eV_s = K_{\text{max}} \] where \( K_{\text{max}} \) signifies the maximum kinetic energy of the emitted photoelectrons. Therefore, the stopping potential is \( \frac{1}{e} \) times this maximum kinetic energy.