Initial matches played by the team = 40.
Number of matches won initially = 30% of 40 = \(\frac{30}{100}×40\) = 12.
Let the number of remaining matches be x.
Number of remaining matches won by the team = 60% of x = \(\frac{60}{100}× x=0.06x\).
The equation derived from the problem statement simplifies to:
\(=12+1.2x=40+x\)
\(=0.2x=16\)
\(=x=\frac{16}{0.2}\)
\(x=80\)
This calculation was based on the team winning 90% of the remaining matches.
Number of remaining matches won by the team = 90% of 80 = \(\frac{90}{100}×80\) = 72.
Total number of matches won by the team in the tournament = 12 + 72 = 84.
The final answer is: 84.
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