Question:medium

In a tournament, a team has played 40 matches so far and won 30% of them. If they win 60% of the remaining matches, their overall win percentage will be 50%. Suppose they win 90% of the remaining matches, then the total number of matches won by the team in the tournament will b

Updated On: Jan 15, 2026
  • 86
  • 84
  • 78
  • 80
Show Solution

The Correct Option is B

Solution and Explanation

Initial matches played by the team = 40.

Number of matches won initially = 30% of 40 = \(\frac{30}{100}×40\) = 12.

Let the number of remaining matches be x.

Number of remaining matches won by the team = 60% of x = \(\frac{60}{100}× x=0.06x\).

The equation derived from the problem statement simplifies to:

\(=12+1.2x=40+x\)

\(=0.2x=16\)

\(=x=\frac{16}{0.2}\)

\(x=80\)

This calculation was based on the team winning 90% of the remaining matches.

Number of remaining matches won by the team = 90% of 80 = \(\frac{90}{100}×80\) = 72.

Total number of matches won by the team in the tournament = 12 + 72 = 84.

The final answer is: 84.

Was this answer helpful?
0


Questions Asked in CAT exam