Question:medium

In a time of \(10\) minutes, the activity of a radioactive sample becomes \[ \frac{1}{\sqrt5} \] times its initial activity. After \(10\) more minutes, if its activity becomes \(K\) times the initial activity, the value of \(K\) is

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Radioactive activity follows \[ \boxed{ A=A_0e^{-\lambda t}. } \] Equal successive time intervals multiply the activity by the same decay factor.
Updated On: Jul 15, 2026
  • \(0.2\)
  • \(5\)
  • \(0.5\)
  • \(2\)
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The Correct Option is A

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