In a metre bridge experiment the balance point is obtained if the gaps are closed by $2$ $\Omega$ and $3\Omega$. A shunt of $X$ $\Omega$ is added to $3$ $\Omega$ resistor to shift the balancing point by $22.5$ cm. The value of $X$ is

Question

In a meter bridge experiment, a resistance of $ 10 \, \Omega $ is balanced by a resistance $ X $ with a balance point at $ 40 \, \mathrm{cm} $. What is the value of $ X $?

Answer 1

Step 1: Check by rebuilding
With $X=2$: $\frac{3\times2}{5}=1.2\,\Omega$. Balance condition: $\frac{l}{100-l}=\frac{2}{1.2}=\frac53$, so $l=62.5$ cm, a shift of $22.5$ cm. This confirms $X=2\,\Omega$.

Final Answer:
Option (B). \[ \boxed{\text{(B)}} \]

In a metre bridge experiment the balance point is obtained if the gaps are closed by \(2\) \(\Omega\) and \(3\Omega\). A shunt of \(X\) \(\Omega\) is added to \(3\) \(\Omega\) resistor to shift the balancing point by \(22.5\) cm. The value of \(X\) is

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The Correct Option is B

Solution and Explanation

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