Question:medium
In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is kJ.
In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is kJ.
Show Hint
In hydraulic systems, work done can be calculated using the force applied and the displacement of the output piston.
Updated On: Jan 14, 2026
Show Solution
Correct Answer: 0.01
Solution and Explanation
The work-energy principle dictates that work equals applied force times displacement. With a force of 100 N and an output piston displacement of 20 cm, the resultant work, converted to kJ, is 0.01 kJ.
Was this answer helpful?
0
Top Questions on Types of forces
A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60° by a force of 10 N parallel to the inclined surface as shown in the figure. When the block is pushed up by 10 m along the inclined surface, the work done against frictional force is:
- JEE Main - 2024
- Physics
- Types of forces
- In a hydraulic lift, the surface area of the input piston is 6 cm² and that of the output piston is 1500 cm². If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is kJ.
- JEE Main - 2025
- Physics
- Types of forces
The torque of a force \(5\^{i}+3\^{j}−7\^{k}\) about the origin is τ. If the force acts on a particle whose position vector is\( 2\^{i}+2\^{j}+\^{k}\), then the value of τ will be
- JEE Main - 2022
- Physics
- Types of forces
- Want to practice more? Try solving extra ecology questions todayView All Questions
