Question:medium

In a code language BANK is coded as DCPM. Then the code for SCHOOL is

Show Hint

If every letter is shifted by \(+2\), apply the same shift to each letter of the word.
  • UEMQQN
  • UFJQQN
  • UEJQQN
  • UJEQQN
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
This problem uses the same coding rule as the previous question. We need to apply the established rule to the word 'SCHOOL'.

Step 2: Key Formula or Approach:

The rule, as determined from the example BANK \(\to\) DCPM, is to shift each letter forward by 2 positions in the alphabet.

Step 3: Detailed Explanation:

The rule is: Original Letter \(\to\) Letter + 2 positions. We apply this rule to the word SCHOOL: - S (19): \(19 + 2 = 21\). The 21st letter is U. - C (3): \(3 + 2 = 5\). The 5th letter is E. - H (8): \(8 + 2 = 10\). The 10th letter is J. - O (15): \(15 + 2 = 17\). The 17th letter is Q. - O (15): \(15 + 2 = 17\). The 17th letter is Q. - L (12): \(12 + 2 = 14\). The 14th letter is N. Combining the letters, the coded word is UEJQQN.

Step 4: Final Answer:

The code for SCHOOL is UEJQQN, which corresponds to option (C).
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