Question:medium

If \[ \overline{F}=(2x^{2}-3z)\mathbf{i}-2xy\mathbf{j}-4x\mathbf{k}, \] then \[ \int_{V}\nabla\cdot\overline{F}\,dV=\_ \] where \(V\) is the closed region bounded by \[ x=0,\quad y=0,\quad z=0,\quad \text{and}\quad x+2y+z=4. \] 

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Always simplify the divergence before setting up the volume integral limits.
  • 0
  • $\frac{2}{3}$
  • $\frac{4}{3}$
  • $\frac{8}{3}$
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The Correct Option is D

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