To find the maximum number of students that passed in all subjects, we use the principle of inclusion-exclusion for three sets: Chemistry (C), Physics (P), and Math (M). Define:
|C| = 16, |P| = 20, |M| = 25, |P ∩ M| = 15, |M ∩ C| = 15, |P ∩ C| = 10.
The formula is:
|C ∪ P ∪ M| = |C| + |P| + |M| - |P ∩ M| - |M ∩ C| - |P ∩ C| + |C ∩ P ∩ M|
Since 40 students are in the class, the inclusion-exclusion principle gives:
40 = 16 + 20 + 25 - 15 - 15 - 10 + |C ∩ P ∩ M|
Solving for |C ∩ P ∩ M|, we have:
40 = 36 + |C ∩ P ∩ M| → |C ∩ P ∩ M| = 40 - 36 = 4.
Therefore, the maximum number of students passing all subjects is 4. Confirming the range 19,19 is not applicable as our obtained solution is formulated under correct constraints.