To solve the given problem, let's analyze the information provided and the statements (a), (b), and (c) to determine their correctness.
The given information is as follows:
- 25\% of families own a phone.
- 15\% of families own a car.
- 65\% of families own neither a phone nor a car.
- 2,000 families own both a car and a phone.
Using this information, we can calculate:
- The percentage of families that own both a phone and a car (P(A \cap B)). Given that 2,000 families own both, it is \left(\frac{2000}{\text{Total number of families}}\right) \times 100\%.
- The percentage of families that own either a phone or a car using the formula for union: P(A \cup B) = P(A) + P(B) - P(A \cap B).
- The total number of families using the fact that 65\% own neither, meaning 100\% - 65\% = 35\% own either a phone, a car, or both.
Let's perform these calculations:
- Since 65\% of families own neither, 35\% of families own either a phone or a car or both. Given this is equal to the union, statement (b) is correct if this percentage matches. We'll verify this calculation:
- Using the union formula:
P(A \cup B) = P(A) + P(B) - P(A \cap B)
35\% = 25\% + 15\% - P(A \cap B)
\Hence, P(A \cap B) = 25\% + 15\% - 35\% = 5\%. This matches 5\% which verifies (a).
- To find the total number of families, equate:
P(A \cap B) = \frac{2000}{\text{Total number of families}} \times 100\% = 5\%
Therefore, \text{Total number of families} = \frac{2000}{0.05} = 40,000. This verifies (c).
Thus, all these calculations confirm statements (a), (b), and (c) are correct:
- (a) 5\% of families own both a car and a phone.
- (b) 35\% of families own either a car or a phone.
- (c) 40,000 families live in the town.
Correct Option: All (a), (b), and (c) are correct.