Question:hard

In a certain town, $25\%$ of the families own a phone and $15\%$ own a car $65\%$ families own neither a phone nor a car and $2,000$ families own both a car and a phone. Consider the following three statements : (a) $5\%$ families own both a car and a phone. (b) $35\%$ families own either a car or a phone. (c) $40,000$ families live in the town. Then,

Updated On: Apr 1, 2026
  • Only (a) and (b) are correct
  • Only (a) and (c) are correct
  • Only (b) and (c) are correct
  • All (a), (b) and (c) are correct
Show Solution

The Correct Option is D

Solution and Explanation

To solve the given problem, let's analyze the information provided and the statements (a), (b), and (c) to determine their correctness.

The given information is as follows:

  • 25\% of families own a phone.
  • 15\% of families own a car.
  • 65\% of families own neither a phone nor a car.
  • 2,000 families own both a car and a phone.

Using this information, we can calculate:

  1. The percentage of families that own both a phone and a car (P(A \cap B)). Given that 2,000 families own both, it is \left(\frac{2000}{\text{Total number of families}}\right) \times 100\%.
  2. The percentage of families that own either a phone or a car using the formula for union: P(A \cup B) = P(A) + P(B) - P(A \cap B).
  3. The total number of families using the fact that 65\% own neither, meaning 100\% - 65\% = 35\% own either a phone, a car, or both.

Let's perform these calculations:

  1. Since 65\% of families own neither, 35\% of families own either a phone or a car or both. Given this is equal to the union, statement (b) is correct if this percentage matches. We'll verify this calculation:
  2. Using the union formula:
    P(A \cup B) = P(A) + P(B) - P(A \cap B)
    35\% = 25\% + 15\% - P(A \cap B)
    \Hence, P(A \cap B) = 25\% + 15\% - 35\% = 5\%. This matches 5\% which verifies (a).
  3. To find the total number of families, equate:
    P(A \cap B) = \frac{2000}{\text{Total number of families}} \times 100\% = 5\%
    Therefore, \text{Total number of families} = \frac{2000}{0.05} = 40,000. This verifies (c).

Thus, all these calculations confirm statements (a), (b), and (c) are correct:

  • (a) 5\% of families own both a car and a phone.
  • (b) 35\% of families own either a car or a phone.
  • (c) 40,000 families live in the town.

Correct Option: All (a), (b), and (c) are correct.

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